\begin{figure}[h]
\centering
\begin{asy}
size (4cm);
pair A, B, C;
A=(3,4);
B=(6,5.5);
C=(5,5);
draw((0,3)--(2,7)--(10,7)--(8,3)--cycle);
draw((4.8,0)--(5,5)--(5.2,0)--cycle);
draw(A--B);
dot("$A$",A,NW);
dot("$B$",B,NE);
dot("$C$",C,N);
draw(A--(A-(0,2)),EndArrow);
label("$m_1$",A-(0,2),SW);
draw(B--(B-(0,1)),EndArrow);
label("$m_2$",B-(0,1),SE);
draw(C--(C+(0,3)),EndArrow);
label("$m_1+m_2$",C+(0,3),N);
\end{asy}
\caption{Force proportional to $m_1+m_2$ must be placed at $C$ to keep the table in equilibrium}
\label{fig:center_of_mass_intuition}
\end{figure}